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Solution

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Correct option is A)

Mass of the planet, $M=Vd=d×34 πR_{3}$ where $d$ is the density of the planet

$⟹$ $g=34 πdGR$ (for earth)

Given : $d_{′}=d$ and $R_{′}=0.2R$

$∴$ $g_{′}=34 πd_{′}GR_{′}=34 πdG(0.2R)$

$⟹$ $g_{′}=0.2g$

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