If the density of a small planet is the same as that of earth, while the radius of the planet is 0.2 times that the earth, the gravitational acceleration on the surface of that planet is:
A
0.2 g
B
0.4 g
C
2 g
D
4 g
Medium
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Solution
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Correct option is A)
Acceleration due to gravity g=R2GM
Mass of the planet, M=Vd=d×34πR3 where d is the density of the planet