If the density of methanol is 0-793- text-kg- - - L - -1 - what is its volume needed making 2-5 L of its 0-25 M solution-

Question

Toppr Admin · Accepted Answer

Mass of methanol required isM-Volume of solution-xD7-Molariy of solution-xD7-Molar mass of methanol-2-5-xD7-0-25-xD7-32-20 g-Volume of methanol needed -massdensity-200-793-25-22 mL-

If the density of methanol is $0.793 kg L^{- 1}$ , what is its volume needed for making $2.5$ L of its $0.25$ M solution?

Mass of methanol required is

$M = Volume of solution \times Molariy of solution \times Molar mass of methanol$

$= 2.5 \times 0.25 \times 32 = 20$ g.

Volume of methanol needed $= \frac{mass}{density} = \frac{20}{0.793} = 25.22$ mL.

If the density of methanol is 0.793kgL−1, what is its volume needed for making 2.5 L of its 0.25 M solution?

Mass of methanol required isM=Volume of solution×Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of methanol needed =massdensity=200.793=25.22 mL.

If the density of methanol is $0.793 kg L^{- 1}$ , what is its volume needed for making $2.5$ L of its $0.25$ M solution?

Mass of methanol required is

$M = Volume of solution \times Molariy of solution \times Molar mass of methanol$

$= 2.5 \times 0.25 \times 32 = 20$ g.

Volume of methanol needed $= \frac{mass}{density} = \frac{20}{0.793} = 25.22$ mL.