If the density of methanol is $0.793 kg L^{- 1}$ , what is its volume needed for making $2.5$ L of its $0.25$ M solution?

Name: If the density of methanol is 0.793 kg L^-1 , what is its volume needed for making 2.5 L of its 0.25 M solution?
Uploaded: 2020-01-06
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Answer 1

Mass of methanol required is

$M = Volume of solution \times Molariy of solution \times Molar mass of methanol$

$= 2.5 \times 0.25 \times 32 = 20$ g.

Volume of methanol needed $= \frac{mass}{density} = \frac{2 0}{0 . 7 9 3} = 25.22$ mL.

Answer 2

Mass of methanol required is

M = Volume of solution \times Molariy of solution \times Molar mass of methanol

= 2.5 \times 0.25 \times 32 = 20

g.

Volume of methanol needed

= \frac{mass}{density} = \frac{2 0}{0 . 7 9 3} = 25.22

mL.

If the density of methanol is $0.793 kg L^{- 1}$ , what is its volume needed for making $2.5$ L of its $0.25$ M solution?

Mass of methanol required is

$M = Volume of solution \times Molariy of solution \times Molar mass of methanol$

$= 2.5 \times 0.25 \times 32 = 20$ g.

Volume of methanol needed $= \frac{mass}{density} = \frac{2 0}{0 . 7 9 3} = 25.22$ mL.

What is the molality m, of methanol in a solution prepared by dissolving $160$ g of methanol in $200.0$ g of water?

What is the quantity of water that should be added to $16$ g methanol to make the mole fraction of methanol as $0.25$ ?

The concentration of a solution is $8$ % (w / w) and $10$ % (w / v). The density of solution is :

The dot at the end of this sentence has a mass of about one microgram. Assuming that the black stuff is carbon, the approximate number of atoms of carbon needed to make such a dot is $5 \times 10^{x}$ atoms. The value of $x$ is:

The volume of water required to make $0.20$ M solution from $16$ ml of $0.5$ M solution is:

Revise with Concepts

Concentration Terms: Molarity

Concentration Terms: Molality

If the density of methanol is 0.793kgL−1, what is its volume needed for making 2.5 L of its 0.25 M solution?

Mass of methanol required is M=Volume of solution×Molariy of solution×Molar mass of methanol =2.5×0.25×32=20 g. Volume of methanol needed =densitymass​=0.79320​=25.22 mL.

What is the molality m, of methanol in a solution prepared by dissolving 160 g of methanol in 200.0 g of water?

What is the quantity of water that should be added to 16 g methanol to make the mole fraction of methanol as 0.25?

The concentration of a solution is 8% (w / w) and 10% (w / v). The density of solution is :

The dot at the end of this sentence has a mass of about one microgram. Assuming that the black stuff is carbon, the approximate number of atoms of carbon needed to make such a dot is 5×10x atoms. The value of x is:

The volume of water required to make 0.20 M solution from 16 ml of 0.5 M solution is:

Revise with Concepts

Concentration Terms: Molarity

Concentration Terms: Molality

If the density of methanol is $0.793 kg L^{- 1}$ , what is its volume needed for making $2.5$ L of its $0.25$ M solution?

Mass of methanol required is

$M = Volume of solution \times Molariy of solution \times Molar mass of methanol$

$= 2.5 \times 0.25 \times 32 = 20$ g.

Volume of methanol needed $= \frac{mass}{density} = \frac{2 0}{0 . 7 9 3} = 25.22$ mL.

What is the molality m, of methanol in a solution prepared by dissolving $160$ g of methanol in $200.0$ g of water?

What is the quantity of water that should be added to $16$ g methanol to make the mole fraction of methanol as $0.25$ ?

The concentration of a solution is $8$ % (w / w) and $10$ % (w / v). The density of solution is :

The dot at the end of this sentence has a mass of about one microgram. Assuming that the black stuff is carbon, the approximate number of atoms of carbon needed to make such a dot is $5 \times 10^{x}$ atoms. The value of $x$ is:

The volume of water required to make $0.20$ M solution from $16$ ml of $0.5$ M solution is: