If the diagonal BD of a quadrilateral ABCD bisects both ∠B and ∠D then, AB=AD
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Solution
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Given: AB=AC ∠ABC=∠ACB (Isoceles triangle property).. (II) Hence, 180−∠ABC=180−∠ACB 12(180−∠ABC)=12(180−∠ACB) ∠DBC=∠DCB ...(I) Adding I and II ∠ABC+∠DBC=∠ACB+∠DCB ∠DBA=∠DCA... (III)
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