If the diameter and height of a right circular cone are $12 c m$ and $8 c m$ respectively, then the slant height is

Question

If the diameter and height of a right circular cone are 12cm and 8cm respectively- then the slant height is20cm30cm10cm96cm

Toppr Admin · Accepted Answer

We have-d-12-xA0-cmr-6-xA0-cmh-8-xA0-cmWe know that the slant heightl-x221A-r2-h2So-l-x221A-62-82l-x221A-36-64l-x221A-100-10-xA0-cmHence- this is the answer-

If the diameter and height of a right circular cone are $12 c m$ and $8 c m$ respectively, then the slant height is
$20 c m$
$30 c m$
$10 c m$
$96 c m$

We have,
$d = 12 c m$
$r = 6 c m$
$h = 8 c m$

We know that the slant height
$l = \sqrt{r^{2} + h^{2}}$

So,
$l = \sqrt{6^{2} + 8^{2}}$

$l = \sqrt{36 + 64}$

$l = \sqrt{100} = 10 c m$

Hence, this is the answer.

If the diameter and height of a right circular cone are 12cm and 8cm respectively, then the slant height is20cm30cm10cm96cm

We have,d=12 cmr=6 cmh=8 cmWe know that the slant heightl=√r2+h2So,l=√62+82l=√36+64l=√100=10 cmHence, this is the answer.

If the diameter and height of a right circular cone are $12 c m$ and $8 c m$ respectively, then the slant height is
$20 c m$
$30 c m$
$10 c m$
$96 c m$

We have,
$d = 12 c m$
$r = 6 c m$
$h = 8 c m$

We know that the slant height
$l = \sqrt{r^{2} + h^{2}}$

So,
$l = \sqrt{6^{2} + 8^{2}}$

$l = \sqrt{36 + 64}$

$l = \sqrt{100} = 10 c m$

Hence, this is the answer.