If the energy and momentum of a photon are E and p respectively, then the velocity of photon will be
$\frac{E}{p}$
$3 \times 10^{8} m / s$
Ep
${(\frac{E}{p})}^{2}$

Question

If the energy and momentum of a photon are E and p respectively- then the velocity of photon will be displaystyle frac-E-p-displaystyle 3times 10-8-m-sEpdisplaystyle left - frac-E-p- right -2-

Toppr Admin · Accepted Answer

Energy of a photon moving with velocity c is given by-E-mc2and momentum of the photon is P-mcSo- the velocity of photon will be-v-E-P-c-3-xD7-108m-sSo- the answers are options -A- -amp- -D-

If the energy and momentum of a photon are E and p respectively, then the velocity of photon will be Ep3×108m/sEp(Ep)2

Energy of a photon moving with velocity c is given by:E=mc2and momentum of the photon is P=mcSo, the velocity of photon will be:v=E/P=c=3×108m/sSo, the answers are options (A) & (D).

If the energy and momentum of a photon are E and p respectively, then the velocity of photon will be
$\frac{E}{p}$
$3 \times 10^{8} m / s$
Ep
${(\frac{E}{p})}^{2}$

Energy of a photon moving with velocity c is given by:
$E = m c^{2}$
and momentum of the photon is
$P = m c$
So, the velocity of photon will be:
$v = E / P = c = 3 \times 10^{8} m / s$
So, the answers are options (A) & (D).