If the energy of the electron in the first orbit of $H -$ atom is $E$ , then the energy of the electron in the first Bohr orbit of $L i^{2 +}$ ion is:

Question

If the energy of the electron in the first orbit of H - atom is E- then the energy of the electron in the first Bohr orbit of Li-2- ion is-4 E9 E3 E2 E

Toppr Admin · Accepted Answer

Energy-x221D-Z2n2For Li2- the number of electrons is 1- Thus- orbit number n-1-Also- for Li the atomic numberZ-3-

If the energy of the electron in the first orbit of $H -$ atom is $E$ , then the energy of the electron in the first Bohr orbit of $L i^{2 +}$ ion is:
$4 E$
$9 E$
$3 E$
$2 E$

$E n e r g y \propto \frac{Z^{2}}{n^{2}}$

For $L i^{2 +}$ , the number of electrons is 1. Thus, orbit number $n = 1$ .

Also, for Li the atomic number $Z = 3$ .

If the energy of the electron in the first orbit of H− atom is E, then the energy of the electron in the first Bohr orbit of Li2+ ion is:4E9E3E2E

Energy∝Z2n2For Li2+, the number of electrons is 1. Thus, orbit number n=1.Also, for Li the atomic numberZ=3.

If the energy of the electron in the first orbit of $H -$ atom is $E$ , then the energy of the electron in the first Bohr orbit of $L i^{2 +}$ ion is:
$4 E$
$9 E$
$3 E$
$2 E$

$E n e r g y \propto \frac{Z^{2}}{n^{2}}$

For $L i^{2 +}$ , the number of electrons is 1. Thus, orbit number $n = 1$ .

Also, for Li the atomic number $Z = 3$ .