If the force is given by F - at-bt-2 with t as time- The dimensions of a and b are-MLT-4- -MLT-2-ML-2T-3- -ML-2T-2-MLT-3- -MLT-4-ML-2T-3- -ML-3T-4-

Question

If the force is given by  F - at-bt-2 with  t  as time- The dimensions of a and b are-MLT-4- -MLT-2-ML-2T-3- -ML-2T-2-MLT-3- -MLT-4-ML-2T-3- -ML-3T-4-

Toppr Admin · Accepted Answer

The correct option is B -MLT-x2212-3-MLT-x2212-4-Dimension of force F - -MLT-x2212-2-F-at-bt2-x27F9- Dimension of a-MLT-x2212-2-xD7-T-x2212-1-MLT-x2212-3-Dimensions of b-MLT-x2212-2-xD7-T-x2212-2-MLT-x2212-4-

If the force is given by $F$ = $a t + b t^{2}$ with $t$ as time. The dimensions of a and b are:
$[M L T^{- 4}], [M L T^{- 2}]$
$[M L^{2} T^{- 3}], [M L^{2} T^{- 2}]$
$[M L T^{- 3}], [M L T^{- 4}]$
$[M L^{2} T^{- 3}], [M L^{3} T^{- 4}]$

The correct option is B $[M L T^{- 3}], [M L T^{- 4}]$
Dimension of force F : $[M L T^{- 2}]$
$F = a t + b t^{2}$
$⟹$ Dimension of $a : [M L T^{- 2}] \times [T^{- 1}]$ $= [M L T^{- 3}]$
Dimensions of $b : [M L T^{- 2}] \times [T^{- 2}]$ $= [M L T^{- 4}]$

If the force is given by F = at+bt2 with t as time. The dimensions of a and b are:[MLT−4],[MLT−2][ML2T−3],[ML2T−2][MLT−3],[MLT−4][ML2T−3],[ML3T−4]

The correct option is B [MLT−3],[MLT−4]Dimension of force F : [MLT−2]F=at+bt2⟹ Dimension of a:[MLT−2]×[T−1]=[MLT−3]Dimensions of b:[MLT−2]×[T−2]=[MLT−4]

If the force is given by $F$ = $a t + b t^{2}$ with $t$ as time. The dimensions of a and b are:
$[M L T^{- 4}], [M L T^{- 2}]$
$[M L^{2} T^{- 3}], [M L^{2} T^{- 2}]$
$[M L T^{- 3}], [M L T^{- 4}]$
$[M L^{2} T^{- 3}], [M L^{3} T^{- 4}]$

The correct option is B $[M L T^{- 3}], [M L T^{- 4}]$
Dimension of force F : $[M L T^{- 2}]$
$F = a t + b t^{2}$
$⟹$ Dimension of $a : [M L T^{- 2}] \times [T^{- 1}]$ $= [M L T^{- 3}]$
Dimensions of $b : [M L T^{- 2}] \times [T^{- 2}]$ $= [M L T^{- 4}]$