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Question

If the H.C.F of 657 and 963 is expressible in the form 657x(963×15), find x.

Solution
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Using Euclid's division
a=bq+r
963=657×1+306
657=306×2+45
306=45×6+36
45=36×1+9
36=9×4+0
H.C.F=9
9=657x(963×15)
657x=14454
x=22

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