If the height and the base area of a right circular cone are $5 c m$ and $48 s q . c m$ respectively, then the volume of the cone is equal to

Question

If the height and the base area of a right circular cone are 5cm and 48sq-cm respectively- then the volume of the cone is equal to240-cm-3-80-cm-3-120-cm-3-480-cm-3-

Toppr Admin · Accepted Answer

We have-h-5-xA0-cmBase area -48-xA0-cm2-x3C0-r2-48-x21D2-r-3-9-xA0-cm-xA0-We know that the volume of the cone-13-x3C0-r2hSo-13-xD7-227-xD7-3-9-2-xD7-5-79-89-x2248-80-xA0-cm3Hence- this is the answer-

If the height and the base area of a right circular cone are $5 c m$ and $48 s q . c m$ respectively, then the volume of the cone is equal to
$240 {c m}^{3}$
$80 {c m}^{3}$
$120 {c m}^{3}$
$480 {c m}^{3}$

We have,
$h = 5 c m$

Base area $= 48 c m^{2}$
$π r^{2} = 48 \Rightarrow r = 3.9 c m$

We know that the volume of the cone
$= \frac{1}{3} π r^{2} h$

So,
$= \frac{1}{3} \times \frac{22}{7} \times (3.9)^{2} \times 5$

$= 79.89 \approx 80 c m^{3}$

Hence, this is the answer.

If the height and the base area of a right circular cone are 5cm and 48sq.cm respectively, then the volume of the cone is equal to240cm380cm3120cm3480cm3

We have,h=5 cmBase area =48 cm2πr2=48⇒r=3.9 cm We know that the volume of the cone=13πr2hSo,=13×227×(3.9)2×5=79.89≈80 cm3Hence, this is the answer.

If the height and the base area of a right circular cone are $5 c m$ and $48 s q . c m$ respectively, then the volume of the cone is equal to
$240 {c m}^{3}$
$80 {c m}^{3}$
$120 {c m}^{3}$
$480 {c m}^{3}$

We have,
$h = 5 c m$

Base area $= 48 c m^{2}$
$π r^{2} = 48 \Rightarrow r = 3.9 c m$

We know that the volume of the cone
$= \frac{1}{3} π r^{2} h$

So,
$= \frac{1}{3} \times \frac{22}{7} \times (3.9)^{2} \times 5$

$= 79.89 \approx 80 c m^{3}$

Hence, this is the answer.