If the length of cylinder is measured to be $4.28cm$ with an error of $0.01cm$, the percentage error in the measured length is nearly

$\text{Step 1 - Given that:}$

length, $l=4.28cm$

         $△l=0.01cm$

$\text{Step 2 - Percentage error is given by}$

$\%error=\frac{△l}{l}\times 100$

               $=\frac{0.01}{4.28}\times 100$

               $=0.234\approx 0.2\%$