If the length of cylinder is measured to be 4.28cm with an error of 0.01cm, the percentage error in the measured length is nearly

0.4%

0.5%

0.2%

0.1%

A

0.4%

B

0.2%

C

0.1%

D

0.5%

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Solution

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Given:Length of the cylinder =l=4.28cm

Error=Δl=0.01cm

Percentage error=Δll×100

=0.014.28×100=0.234≈0.2%

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