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Question

If the mean and variance of a binomial distribution are $$18$$ and $$12$$. Find $$n$$

Solution
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$$\textbf{Step 1: Use mean and variance formula of binomial distribution to find probability of failure.}$$

$$\text{Mean}$$ $$=n
p=18$$ $$......(1)$$

$$\text{Variance}$$ $$=n
p q=12$$ $$......(2)$$

$$\text{Substitute, }np=18 \text{ in equation (2), we get}$$

$$18 \times q=12$$

$$\text{Probability of failure}=q=\dfrac{2}{3}$$ $$......(3)$$


$$\textbf{Step 2: Find probability of success and then number of trails.}$$

$$p=1-q$$

$$\Rightarrow p=1-\dfrac{2}{3}$$

$$\Rightarrow p=\dfrac{1}{3}$$

$$ \begin{aligned} &n p=18 \\\\ &n=\dfrac{18}{p} \quad \quad \quad \textbf{[From eqn(i)]}\end{aligned} $$

$$\Rightarrow n=\dfrac{18}{\dfrac{1}{3}} $$

$$\Rightarrow n=18 \times 3 $$

$$\Rightarrow n=54$$

$$\textbf{Hence, number of trails }\boldsymbol{=n=54.}$$

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