If the mean of the observations-x- x - 3- x - 5- x - 7- x - 10 is 9- the mean of the last three observations is10dfrac-2-3-10dfrac-1-3-11dfrac-1-3-11dfrac-2-3-

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Toppr Admin · Accepted Answer

Mean of-xA0-x-x-3-x-5-x-7-x-10-9Sum of the terms -5x-25Mean - 5x-255-9x-5-9x-4Last three observations are 9-11-14Mean -9-11-143-1113

If the mean of the observations:
$x, x + 3, x + 5, x + 7, x + 10$ is $9$ , the mean of the last three observations is
$10 \frac{2}{3}$
$10 \frac{1}{3}$
$11 \frac{1}{3}$
$11 \frac{2}{3}$

Mean of $x, x + 3, x + 5, x + 7, x + 10 = 9$
Sum of the terms $= 5 x + 25$
Mean = $\frac{5 x + 25}{5} = 9$
$x + 5 = 9$
$x = 4$
Last three observations are $9, 11, 14$
Mean $= \frac{9 + 11 + 14}{3} = 11 \frac{1}{3}$

If the mean of the observations:x,x+3,x+5,x+7,x+10 is 9, the mean of the last three observations is1023101311131123

Mean of x,x+3,x+5,x+7,x+10=9Sum of the terms =5x+25Mean = 5x+255=9x+5=9x=4Last three observations are 9,11,14Mean =9+11+143=1113

If the mean of the observations:
$x, x + 3, x + 5, x + 7, x + 10$ is $9$ , the mean of the last three observations is
$10 \frac{2}{3}$
$10 \frac{1}{3}$
$11 \frac{1}{3}$
$11 \frac{2}{3}$

Mean of $x, x + 3, x + 5, x + 7, x + 10 = 9$
Sum of the terms $= 5 x + 25$
Mean = $\frac{5 x + 25}{5} = 9$
$x + 5 = 9$
$x = 4$
Last three observations are $9, 11, 14$
Mean $= \frac{9 + 11 + 14}{3} = 11 \frac{1}{3}$