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Question

If the mean of variate X in distribution 2.6, then the value of k is
Variate X 1 2 3 4 5
Frequency of X 4 5 k 1 2

$8$
$10$
$12$
$18$

A

8

B

10

C

12

D

18

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Solution

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$\frac{1 \times 4 + 2 \times 5 + 3 \times k + 4 \times 1 + 5 \times 2}{4 + 5 + k + 1 + 2} = 2.6$
$\Rightarrow 0.4 k = 3.2 \Rightarrow k = 8$

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Q1

If the mean of variate X in distribution 2.6, then the value of k is

Variate X	1	2	3	4	5
Frequency of X	4	5	k	1	2

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Q2

If the mean of x in distribution

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Q3

If the mean of the following distribution is 2.6, then the value of y is

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Q5

If the mean of the following frequency distribution is

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