Given molarity of the solution =0.2
Volume of solution =200ml=0.2 L
Molarity=Moles of soluteVolume in litres
Moles of solute =0.2×0.2=0.04
No. of moles=Given massMolar mass
Molar mass of C6H12O6=6×12+12+6×16=180g
Mass of glucose in the solution = 180×0.04=7.2g