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Question

If the mth,nth and pth terms of an A.P. and G.P. are equal and are x, y, z then xyzyzxzxy is equal to-

Solution
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Then x=a+(m1)d and x=brm1
y=a+(n1)d and y=brn1
z=a+(p1)d and z=brp1
xy=(mn)d,yz=(np)d,zx=(pm)d
Now xyz,yzx,zxy=[brm1](np)d[brn1](pm)d[drp1](mn)d
=b[np+pm+mn]dr[(m1)(np)+(n1)(pm)+(m+n)]d
=b0.dr0.d=1

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