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If the numerator of a fraction is increased by $20 %$ and the denominator is decreased by $5 %$ , the value of the new fraction becomes $\frac{5}{2}$ . The original fraction is:
$\frac{15}{19}$
$\frac{3}{18}$
$\frac{95}{48}$
$\frac{48}{95}$

A

\frac{48}{95}

B

\frac{3}{18}

C

\frac{95}{48}

D

\frac{15}{19}

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Q1

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