If the particle were negatively charged then what will be the magnitude of force on the charged particle?
zero
$23.04 \times 10^{- 6} N$
None of these
$230.4 \times 10^{- 5} N$

Question

If the particle were negatively charged then what will be the magnitude of force on the charged particle-zero23-04times -10-6-NNone of these230-4times -10-5-N

Toppr Admin · Accepted Answer

Force acting on a charged particle moving in a magnetic field is

$\to F = q (\to v \times \to B)$

$⟹ ∣ ∣ \to F ∣ ∣ = | - e | v B = e v B$

$= 1.6 \times 10^{- 19} \times 4.8 \times 10^{6} \times 30 \times 10^{6} N$

$= 23.04 \times 10^{- 6} N$ .

If the particle were negatively charged then what will be the magnitude of force on the charged particle?zero23.04×10−6NNone of these230.4×10−5N

Force acting on a charged particle moving in a magnetic field is →F=q(→v×→B)⟹∣∣→F∣∣=|−e|vB=evB=1.6×10−19×4.8×106×30×106N=23.04×10−6N.

If the particle were negatively charged then what will be the magnitude of force on the charged particle?
zero
$23.04 \times 10^{- 6} N$
None of these
$230.4 \times 10^{- 5} N$

Force acting on a charged particle moving in a magnetic field is

$\to F = q (\to v \times \to B)$

$⟹ ∣ ∣ \to F ∣ ∣ = | - e | v B = e v B$

$= 1.6 \times 10^{- 19} \times 4.8 \times 10^{6} \times 30 \times 10^{6} N$

$= 23.04 \times 10^{- 6} N$ .