Solve

Guides

Analysis of Force Equation

Question

If the particle were negatively charged then what will be the magnitude of force on the charged particle?

A

23.04 \times 10^{- 6} N

B

230.4 \times 10^{- 5} N

C

zero

D

None of these

Open in App

Solution

Verified by Toppr

Force acting on a charged particle moving in a magnetic field is

$\to F = q (\to v \times \to B)$

$⟹ ∣ ∣ \to F ∣ ∣ = | - e | v B = e v B$

$= 1.6 \times 10^{- 19} \times 4.8 \times 10^{6} \times 30 \times 10^{6} N$

$= 23.04 \times 10^{- 6} N$ .

Was this answer helpful?

0

Similar Questions

Q1

The sum of the magnitudes of two forces is $18 N$ and the magnitude of their resultant is $12 N$ . If the resultant makes an angle of $90^{\circ}$ with the smaller force, then find the magnitude of the forces.

View Solution

Q2

What is the nature of the force which is experienced between a negatively charged particle and a positively charged particle?

View Solution

Q3

The force on the charged particle in magnitude is

View Solution

Q4

Assertion :If a positively charged particle is placed in front of a spherical uncharged conductor. The number of lines of forces terminating on the sphere will be more than those emerging from it. Reason: The surface charge density at a point on the sphere nearest to the point charge will be negative and maximum in magnitude compared to other points on the sphere.

View Solution

Q5

A charged particle carrying electric charge of + 10 $μ$ C is to rest on the horizontal surface of a table when another charged particle carrying a charge of +10 $μ$ C is at a distance of 20 m from 10 $μ$ C. Determine the magnitude and direction of the frictional force acting on the charged particle placed on the table.

View Solution

Solve

Guides