If the pH of pure water is 7- then the hydrogen ion concentration- -H- in mol L-1- will be-70-10-7-10-7-

Question

Toppr Admin · Accepted Answer

We know that -xA0-pH-x2212-log-xA0-H-Given- pH-7So- 7-x2212-log-xA0-H-log-xA0-H-x2212-7-x27F9-H-10-x2212-7Hence- the hydrogen ion concentration is 10-x2212-7 mol L-x2212-1-

If the pH of pure water is $7$ , then the hydrogen ion concentration, $[H^{+}]$ in mol L $^{- 1}$ will be:
$7$
$0$
$10^{- 7}$
$10^{+ 7}$

We know that $p H = - l o g [H^{+}]$

Given, $p H = 7$

So, $7 = - l o g [H^{+}]$

$l o g [H^{+}] = - 7 ⟹ [H^{+}] = 10^{- 7}$

Hence, the hydrogen ion concentration is $10^{- 7}$ mol L $^{- 1}$ .

If the pH of pure water is 7, then the hydrogen ion concentration, [H+] in mol L−1 will be:7010−710+7

We know that pH=−log [H+]Given, pH=7So, 7=−log [H+]log [H+]=−7⟹[H+]=10−7Hence, the hydrogen ion concentration is 10−7 mol L−1.

If the pH of pure water is $7$ , then the hydrogen ion concentration, $[H^{+}]$ in mol L $^{- 1}$ will be:
$7$
$0$
$10^{- 7}$
$10^{+ 7}$

We know that $p H = - l o g [H^{+}]$

Given, $p H = 7$

So, $7 = - l o g [H^{+}]$

$l o g [H^{+}] = - 7 ⟹ [H^{+}] = 10^{- 7}$

Hence, the hydrogen ion concentration is $10^{- 7}$ mol L $^{- 1}$ .