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Question

If the point (x,y) is equidistant from (a,0) and (2a,a) then
x=y=a
x+y=2a
x-y=a
x-y=2a

A

x+y=2a

B

x=y=a

C

x-y=2a

D

x-y=a

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Solution

Verified by Toppr

${(x - a)}^{2} + {(y - 0)}^{2} = {(x - 2 a)}^{2} + {(y - a)}^{2}$
or $x^{2} - 2 a x + a^{2} + y^{2} = x^{2} - 4 a x + 4 a^{2} + y^{2} - 2 a y + a$
or 2ax + 2ay = $4 a^{2}$
or x+y = 2a

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