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Question

If the points (a,0), (0,b), and (1,1) are collinear then
$\frac{1}{a} + \frac{1}{b} = 1$
a+b=1
a+b=2
$\frac{1}{a} - \frac{1}{b} = 1$

A

\frac{1}{a} + \frac{1}{b} = 1

B

a+b=1

C

a+b=2

D

\frac{1}{a} - \frac{1}{b} = 1

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Solution

Verified by Toppr

a(b - 1) + 0 + 1 (0 - b) = 0
or ab = $a + b$
or $\frac{1}{a} + \frac{1}{b} = 1$

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