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Question

If the potential difference applied to the photoelectric tube is doubled and the separation between the filament and the target is also doubled, then the cut off wavelength:
  1. will remain uncharged.
  2. will be doubled.
  3. will be halved.
  4. will become four times the original.

A
will remain uncharged.
B
will be doubled.
C
will be halved.
D
will become four times the original.
Solution
Verified by Toppr

The cut off wavelength corresponds to the work function of the material:
W=hcλ
where λ is the cutoff wavelength. Work function is independent of the electric field applied externally to the material, therefore the cut off wavelength will remain unchanged.

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