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>>Structure of Atom
>>Filling of Orbitals in Atom
>> $If the principle quantum number n = 6, t$

Question

If the principle quantum number n = 6, the correct sequence of filling of electron will be :

A

$n s \to$ $(n - 2) f$ $\to$ np $\to (n - 1)$

B

$n s \to$ $(n - 1) f$ $\to$ $n p$ $\to (n - 2)$

C

$n s \to n p \to (n - 1) d \to (n - 2) f$

D

$n s \to (n - 2) f \to (n - 1) d \to n p$

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Updated on : 2022-09-05

Solution

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Correct option is D)

If the principle quantum number n = 6, the correct sequence of filling of electron will be:

$n s \to (n - 2) f \to (n - 1) d \to$ np.

Here, $n = 6$ . Hence, the correct sequence of filling of electron will be $6 s \to 4 f \to 5 d \to$ $6 p$ .

Hence, option D is correct.

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