If the principle quantum number n = 6, the correct sequence of filling of electron will be :

Question

Verified by Toppr

Answer 1

If the principle quantum number n = 6, the correct sequence of filling of electron will be $n s \to (n - 2) f \to (n - 1) d \to$ np.

Here, $n = 6$ . Hence, the correct sequence of filling of electron will be $6 s \to 4 f \to 5 d \to$ $6 p$ .

Answer 2

If the principle quantum number n = 6, the correct sequence of filling of electron will be

n s \to (n - 2) f \to (n - 1) d \to

np.

Here,

n = 6

. Hence, the correct sequence of filling of electron will be

6 s \to 4 f \to 5 d \to

6 p

.

If the principle quantum number n = 6, the correct sequence of filling of electron will be :

$n s \to$ $(n - 2) f$ $\to$ np $\to (n - 1)$

$n s \to$ $(n - 1) f$ $\to$ $n p$ $\to (n - 2)$

$n s \to n p \to (n - 1) d \to (n - 2) f$

$n s \to (n - 2) f \to (n - 1) d \to n p$

Solution

If the principle quantum number n = 6, the correct sequence of filling of electron will be $n s \to (n - 2) f \to (n - 1) d \to$ np.

Here, $n = 6$ . Hence, the correct sequence of filling of electron will be $6 s \to 4 f \to 5 d \to$ $6 p$ .

Video Explanation

Patterns of problems

Was this answer helpful?

Similar questions

Which of the following sets of quantum numbers is correct for an electron in 4f orbital?

Which of the following sets of quantum numbers is correct for an electron in 4f orbital?

Which of the following statements on quantum numbers is not correct?

Which of the following sets of quantum numbers is correct for an electron in $4 f -$ orbital?

Which of the following are not correct representation for $H$ -atom $u$ , is speed of electron and $n$ is principle quantum number?

More From Chapter

Structure of Atom

Shortcuts & Tips

Common Misconceptions

Cheatsheets

Memorization tricks

Diagram set

Mindmap

Problem solving tips

Practice more questions

3 Qs

2 Qs

2 Qs

4 Qs

108 Qs

698 Qs

If the principle quantum number n = 6, the correct sequence of filling of electron will be :

ns→ (n−2)f → np →(n−1)

ns→ (n−1)f → np →(n−2)

ns→np→(n−1)d→(n−2)f

ns→(n−2)f→(n−1)d→np

If the principle quantum number n = 6, the correct sequence of filling of electron will be ns→(n−2)f→(n−1)d→np. Here, n=6. Hence, the correct sequence of filling of electron will be 6s→4f→5d→6p.

Video Explanation

Patterns of problems

Was this answer helpful?

Similar questions

Which of the following sets of quantum numbers is correct for an electron in 4f orbital?

Which of the following sets of quantum numbers is correct for an electron in 4f orbital?

Which of the following statements on quantum numbers is not correct?

Which of the following sets of quantum numbers is correct for an electron in 4f−orbital?

Which of the following are not correct representation for H-atom u, is speed of electron and n is principle quantum number?

More From Chapter

Structure of Atom

Shortcuts & Tips

Common Misconceptions

Cheatsheets

Memorization tricks

Diagram set

Mindmap

Problem solving tips

Practice more questions

3 Qs

2 Qs

2 Qs

4 Qs

108 Qs

698 Qs

$n s \to$ $(n - 2) f$ $\to$ np $\to (n - 1)$

$n s \to$ $(n - 1) f$ $\to$ $n p$ $\to (n - 2)$

$n s \to n p \to (n - 1) d \to (n - 2) f$

$n s \to (n - 2) f \to (n - 1) d \to n p$

If the principle quantum number n = 6, the correct sequence of filling of electron will be $n s \to (n - 2) f \to (n - 1) d \to$ np.

Here, $n = 6$ . Hence, the correct sequence of filling of electron will be $6 s \to 4 f \to 5 d \to$ $6 p$ .

Which of the following sets of quantum numbers is correct for an electron in $4 f -$ orbital?

Which of the following are not correct representation for $H$ -atom $u$ , is speed of electron and $n$ is principle quantum number?