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Rutherford's Model

Question

If the radius of a nucleus is $6.6$ fermi. Find its mass number, where $R_{0} = 1.1$ fermi
$3$
$216$
$36$
$1$

A

36

B

1

C

3

D

216

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Solution

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$Radius of Nucleus,$
$R = R_{0} A^{1 / 3}$
$Where "A" is Mass Number$
$Given, R = 6.6 fermi, R_{0} = 1.1 fermi$
$\begin{matrix} 6 \cdot 6 = 1 \cdot 1 & A^{1 / 3} A^{1 / 3} = 6 A = 6^{3} \end{matrix}$
$= 216$

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