If the radius of a sphere is doubled what is the ratio of the volume of the first sphere to that of the second?
$2 : 8$
$1 : 2$
$1 : 3$
$1 : 8$

Question

If the radius of a sphere is doubled what is the ratio of the volume of the first sphere to that of the second-2-81-21-31-8

Toppr Admin · Accepted Answer

Let the radius be r If the radius is doubled the new radius will be 2r ThereforeRatio of volumes -43-x3C0-r3-43-x3C0-2r-3-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-r3-8r3-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-1-8

If the radius of a sphere is doubled what is the ratio of the volume of the first sphere to that of the second?2:81:21:31:8

Let the radius be r If the radius is doubled the new radius will be 2r ThereforeRatio of volumes =43πr3:43π(2r)3 =r3:8r3 =1:8

If the radius of a sphere is doubled what is the ratio of the volume of the first sphere to that of the second?
$2 : 8$
$1 : 2$
$1 : 3$
$1 : 8$

Let the radius be $r$ If the radius is doubled the new radius will be $2 r$ Therefore
Ratio of volumes $= \frac{4}{3} π r^{3} : \frac{4}{3} π {(2 r)}^{3}$
$= r^{3} : 8 r^{3}$
$= 1 : 8$