If the radius of the base of a right circular cone is 3r and its height is equal to the radius of the base, then its volume is

(a) $\frac{1}{3} {πr}^{3}$

(b) $\frac{2}{3} {πr}^{3}$

(c) $3 {πr}^{3}$

(d) 9 ${πr}^{3}$

Question

If the radius of the base of a right circular cone is 3r and its height is equal to the radius of the base, then its volume is

(a)

\frac{1}{3} {πr}^{3}

(b)

\frac{2}{3} {πr}^{3}

(c)

3 {πr}^{3}

(d) 9

{πr}^{3}

Toppr Admin · Accepted Answer

If the radius of the base of a right circular cone is 3 r and its height is equal to the radius of the base, then its volume is: (a) \( \frac { 1 } { 2 } \pi \mathrm { r } ^ { 3 } \) (b) \( \frac { 2 } { 2 } \pi \mathrm { r } ^ { 3 } \) (d) 9\( \pi r ^ { 3 } \)