If the solubility of Ag-2-CrO-4- is S mole-lit- Then its solubility product is-S-2-S-3-4S-3-2S-3-

Question

Toppr Admin · Accepted Answer

Ag2CrO4-s-x21D4-2Ag-CrO2-x2212-4-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- 2S -xA0- -xA0- -xA0- -xA0- -xA0- -xA0-SKsp-Ag-2-xD7-CrO2-x2212-4-Ksp-2S-2-xD7-S-4S3Hence- option C is correct-

If the solubility of $A g_{2} C r O_{4}$ is $S$ mole/lit. Then its solubility product is:
$S^{2}$
$S^{3}$
$4 S^{3}$
$2 S^{3}$

$A g_{2} C r O_{4} (s) \Leftrightarrow 2 A g^{+} + C r O_{4}^{2 -}$
$2 S$ $S$

$K_{s p} = [A g^{+}]^{2} \times [C r O_{4}^{2 -}]$

$K_{s p} = (2 S)^{2} \times S = 4 S^{3}$

Hence, option C is correct.

If the solubility of Ag2CrO4 is S mole/lit. Then its solubility product is:S2S34S32S3

Ag2CrO4(s)⇔2Ag++CrO2−4 2S SKsp=[Ag+]2×[CrO2−4]Ksp=(2S)2×S=4S3Hence, option C is correct.

If the solubility of $A g_{2} C r O_{4}$ is $S$ mole/lit. Then its solubility product is:
$S^{2}$
$S^{3}$
$4 S^{3}$
$2 S^{3}$

$A g_{2} C r O_{4} (s) \Leftrightarrow 2 A g^{+} + C r O_{4}^{2 -}$
$2 S$ $S$

$K_{s p} = [A g^{+}]^{2} \times [C r O_{4}^{2 -}]$

$K_{s p} = (2 S)^{2} \times S = 4 S^{3}$

Hence, option C is correct.