If the straight lines AB and XY intersect at the point O and ∠AOX=3∠XOB, then the four angles formed at O are:
30∘,30∘,150∘,150∘
45∘,135∘,90∘,90∘
45∘,45∘,135∘,135∘
30∘,30∘,90∘,210∘
A
30∘,30∘,90∘,210∘
B
30∘,30∘,150∘,150∘
C
45∘,135∘,90∘,90∘
D
45∘,45∘,135∘,135∘
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Solution
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As AB is straight line, let angle AOX = X` then
So,3X+X=180°
x=45°
3X=135°
Opposite angle will be equal,
so, other 2 angles will be 45° and 135°
Answer (D) 45°,45°,135°,135°
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