Let the three numbers in A.P. be a−d,a, and a+d
According to given information
Sum=(a−d)+(a)+(a+d)=24...(1)⇒3a=24∴a=8& Product=(a−d)a(a+d)=440...(2)⇒(8−d)(8)(8+d)=440⇒(8−d)(8+d)=55⇒64−d2=55⇒d2=64−55=9⇒d=±3
Therefore when d=3, the numbers are
5,8,11 and
when d=−3, the
numbers are 11,8 and 5.
Thus the
three numbers are 5,8 and 11.