If the wavelength is equal to the distance travelled by the electron in one second, then:
λ = hp
λ = hm
λ = √hp
λ = √hm
A
λ = √hp
B
λ = hp
C
λ = √hm
D
λ = hm
Open in App
Solution
Verified by Toppr
As we know,
λ = hmv
But v2=hm
By putting this in the equation, we get
λ = √hm
Hence, the correct option is D
Was this answer helpful?
4
Similar Questions
Q1
If the wavelength is equal to the distance travelled by the electron in one second then,
A) wavelength =h/p . B) wavelength=h/m . C) wavelength=(h/p)1/2 D) wavelength = (h/m)1/2
View Solution
Q2
The amount of heat radiated per second by a body of surface area 20cm2 kept at temperature 27oC is H and wavelength having maximum share of emission is λ, find H and λ approximately (e = emissivity = 0.6, σ=6×10−6wattm2K4 Wein's constant =0.288cm−K)
View Solution
Q3
An electron make transition from orbit number N to Pth orbit in H−atom and emit the photon of wavelength (λ). In orbit P, velocity of electron in H−atom is maximum. Which of the following wavelength (λ) is not possible?
(Where 1/R=912A)
View Solution
Q4
The relation p=hλ is valid for
View Solution
Q5
The energy of an electron having de-Broglie wavelength ′λ′ is: