If the wheel of a carriage 500 cm in circumference takes frac-1-2- second to complete one revolution- the rate of the carriage per hour will be reduced by 3 km-h- How fast is the carriage travelling -

Question

Toppr Admin · Accepted Answer

2-x3C0-r-500-xA0-cmSpeed -5001-2-1000-xA0-cm-secSpeed -10-xA0-m-sec-36-xA0-km-hNow after reducing speed by 3-xA0-km-hSpeed -36-3-33-xA0-km-h

If the wheel of a carriage $500$ cm in circumference takes $\frac{1}{2}$ second more to complete one revolution, the rate of the carriage per hour will be reduced by $3$ km/h. How fast is the carriage travelling ?

$2 π r = 500 c m$

Speed $= \frac{500}{1 / 2} = 1000 c m / s e c$

Speed $= 10 m / s e c = 36 k m / h$

Now after reducing speed by $3 k m / h$

Speed $= 36.3 = 33 k m / h$

If the wheel of a carriage 500 cm in circumference takes 12 second more to complete one revolution, the rate of the carriage per hour will be reduced by 3 km/h. How fast is the carriage travelling ?

2πr=500 cmSpeed =5001/2=1000 cm/secSpeed =10 m/sec=36 km/hNow after reducing speed by 3 km/hSpeed =36.3=33 km/h

If the wheel of a carriage $500$ cm in circumference takes $\frac{1}{2}$ second more to complete one revolution, the rate of the carriage per hour will be reduced by $3$ km/h. How fast is the carriage travelling ?

$2 π r = 500 c m$

Speed $= \frac{500}{1 / 2} = 1000 c m / s e c$

Speed $= 10 m / s e c = 36 k m / h$

Now after reducing speed by $3 k m / h$

Speed $= 36.3 = 33 k m / h$