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Algebra of Events

Question

If two events $$A$$ and $$B$$ are such that $$P(A) > 0$$ and $$P(B)\neq 1$$, then $$P(\bar A /\bar B)$$ is equal to

A

$$1-P(A /B)$$

B

$$\dfrac {P(A)}{P(\bar B)}$$

C

$$1-P(\bar A /B)$$

D

$$\dfrac {1-P(A \cup B)}{P(\bar B)}$$

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Solution

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Correct option is C. $$\dfrac {1-P(A \cup B)}{P(\bar B)}$$

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