If two similarly charged particles are brought near one another, the potential energy of the system will :
decrease
increase
remains the same
equal to the K.E.
A
increase
B
remains the same
C
decrease
D
equal to the K.E.
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Solution
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Electrostatic P.E=KQ1Q2r where K=14πϵo
Now for both similar charges, P.E>0
Thus decreasing r will increase P.E
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