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Question

If velocity of a particle is three times of that of electron and ratio of de Broglie wavelength of particle to that of electron is 1.814×104. The particle will be :
  1. Neutron
  2. Deutron
  3. Alpha
  4. Tritium

A
Tritium
B
Neutron
C
Deutron
D
Alpha
Solution
Verified by Toppr

The correct option is A Neutron
de broglie wavelength, λ=hp
λ=hmv

λpλe=mevempvp

mp=mevevp×λeλp

Here, me=9.1×1031kg,vp=3ve and λpλe=1.814×104
mp=9.1×10311.814×104×3=1.672×1027kg

Thus, the particle is neutron.

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