If volume ratio of 0-02M HCl and 0-02M BOH -a weak base- mixed to 200 mL of buffer of pH-7 is 2-23-X- The value of X is- -K-b- BOH-8-1times -10-8-150-22-5

Question

If volume ratio of 0-02M HCl and 0-02M BOH -a weak base- mixed to 200 mL of buffer of pH-7  is 2-23-X- The value of X is- -K-b- BOH-8-1times -10-8-150-22-5

Toppr Admin · Accepted Answer

PKb-x2212-logKb-x2212-log-8-1-xD7-10-x2212-8-7-096

If volume ratio of $0.02 M$ $H C l$ and $0.02 M$ $B O H$ (a weak base) mixed to make $200$ mL of buffer of $p H = 7$ is $2.23 : X$ . The value of $X$ is:

$K_{b}$ for $B O H = 8.1 \times 10^{- 8}$ .

1
5
0.2
2.5

$p K_{b} = - l o g K_{b} = - l o g (8.1 \times 10^{- 8}) = 7.096$

If volume ratio of 0.02M HCl and 0.02M BOH (a weak base) mixed to make 200 mL of buffer of pH=7 is 2.23:X. The value of X is:Kb for BOH=8.1×10−8.150.22.5

pKb=−logKb=−log(8.1×10−8)=7.096

If volume ratio of $0.02 M$ $H C l$ and $0.02 M$ $B O H$ (a weak base) mixed to make $200$ mL of buffer of $p H = 7$ is $2.23 : X$ . The value of $X$ is:

$K_{b}$ for $B O H = 8.1 \times 10^{- 8}$ .

1
5
0.2
2.5

$p K_{b} = - l o g K_{b} = - l o g (8.1 \times 10^{- 8}) = 7.096$