If x- - 2- sqrt3- - 2- sqrt2 and displaystyle frac-1-x- is equal to displaystyle frac-sqrt3- - sqrt2-m- then value of m is -

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Toppr Admin · Accepted Answer

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If $x = 2 \sqrt{3} + 2 \sqrt{2}$ and $\frac{1}{x}$ is equal to $\frac{\sqrt{3} - \sqrt{2}}{m}$ , then value of $m$ is :

$x = 2 \sqrt{3} + 2 \sqrt{2}$
and $\frac{1}{x} = \frac{1}{2 \sqrt{3} + 2 \sqrt{2}} = \frac{(2 \sqrt{3} - 2 \sqrt{2})}{(2 \sqrt{3} - 2 \sqrt{2}) \times (2 \sqrt{3} + 2 \sqrt{2})} = \frac{(\sqrt{3} - \sqrt{2})}{2}$ .
Hence, on comparing, $m = 2$ .

If x=2√3+2√2 and 1x is equal to √3−√2m, then value of m is :

x=2√3+2√2and 1x=12√3+2√2=(2√3−2√2)(2√3−2√2)×(2√3+2√2)=(√3−√2)2.Hence, on comparing, m=2.

If $x = 2 \sqrt{3} + 2 \sqrt{2}$ and $\frac{1}{x}$ is equal to $\frac{\sqrt{3} - \sqrt{2}}{m}$ , then value of $m$ is :

$x = 2 \sqrt{3} + 2 \sqrt{2}$
and $\frac{1}{x} = \frac{1}{2 \sqrt{3} + 2 \sqrt{2}} = \frac{(2 \sqrt{3} - 2 \sqrt{2})}{(2 \sqrt{3} - 2 \sqrt{2}) \times (2 \sqrt{3} + 2 \sqrt{2})} = \frac{(\sqrt{3} - \sqrt{2})}{2}$ .
Hence, on comparing, $m = 2$ .