$$\textbf{Step 1: Subtracting the given expressions}$$
$$\begin{aligned}\left(3 x^{2} y+\right.&\left.2 y^{2}+5\right)-\left(x^{2} y+y^{2}+3\right)=3 x^{2} y+2 y^{2}+5-x^{2} y-y^{2}-3 \\&=\left(3 x^{2} y-x^{2} y\right)+\left(2 y^{2}-y^{2}\right)+(5-3) \text { (Grouping like terms) } \\&=2 x^{2} y+y^{2}+2\end{aligned}$$
$$\textbf{Step 2: Identify the coefficient of the variable y}$$
In the expression $$2 x^{2} y+y^{2}+2$$, the term $$2 x^{2} y$$, has variable $$y$$.
We can see that $$2 x^{2}$$ is the coefficient of $$y$$, in the term $$2 x^{2} y$$.
Therefore, $$2 x^{2}$$ is the coefficient of $$y$$, in $$2 x^{2} y+y^{2}+2$$
$$\textbf{Hence, the coefficient of y in the given result is } 2x^2$$