If $$ x = 8 $$ and $$ y = 2 $$ , evaluate :
$$ (4y)^2 $$
The value of $$ (4y)^2 $$ for $$ x = 8 $$ and $$ y = 2 $$ is calculated as follows,
$$\text{Putting the value of x, y in given equation. }$$
$$ (4y)^2 = (4 \times 2)^2 $$
$$ = (8)^2 $$
$$ = 64 $$
Hence, the value of $$ (4y)^2 $$ for $$ x = 8 $$ and $$ y = 2 $$ is $$ 64 $$