If -x- a- is a factor of -2x-2 -2ax -5x- 10- - the value of a-

Question

Toppr Admin · Accepted Answer

Given - -x-a- is a factor of - 2x-2 - -2a-5-x -10-which shows that one of the zeroes of the given polynomial is -a-160-Now- -x - -a- satisfy the given polynomial- 2-a-2 - -2a - 5-a- -10 - 0- - 2a-2- 2a-2 -5a -10 - 0-5a -10 - a - 2 -

If $$(x+ a)$$ is a factor of $$(2x^2 +2ax +5x+ 10) $$, find the value of $$a.$$

Given : $$(x+a)$$ is a factor of $$ 2x^2 + (2a+5)x +10$$
which shows that one of the zeroes of the given polynomial is $$-a$$
Now, $$x = -a$$ satisfy the given polynomial
$$ 2(-a)^2 + (2a + 5)(-a) +10 = 0$$
$$ 2a^2- 2a^2 -5a +10 = 0$$
$$5a =10 $$
$$ a = 2 $$

If $$(x+ a)$$ is a factor of $$(2x^2 +2ax +5x+ 10) $$, find the value of $$a.$$

Given : $$(x+a)$$ is a factor of $$ 2x^2 + (2a+5)x +10$$which shows that one of the zeroes of the given polynomial is $$-a$$ Now, $$x = -a$$ satisfy the given polynomial$$ 2(-a)^2 + (2a + 5)(-a) +10 = 0$$ $$ 2a^2- 2a^2 -5a +10 = 0$$$$5a =10 $$$$ a = 2 $$

Given : $$(x+a)$$ is a factor of $$ 2x^2 + (2a+5)x +10$$
which shows that one of the zeroes of the given polynomial is $$-a$$
Now, $$x = -a$$ satisfy the given polynomial
$$ 2(-a)^2 + (2a + 5)(-a) +10 = 0$$
$$ 2a^2- 2a^2 -5a +10 = 0$$
$$5a =10 $$
$$ a = 2 $$