If x is 20- than y - find- dfrac x-y - x-

Question

Toppr Admin · Accepted Answer

Consider -y - 100 -Reduction - 20- - 20-160-x - 100 - 20-80-dfrac x - - y-x- - -dfrac-80-100-80-So we get - -dfrac-80-20-160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- Dividing by 20-160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -160- -dfrac 41 - 4-

If x is 20% less than y , find: $$\dfrac x{y - x}$$

Consider $$y = 100 $$
Reduction $$= 20\% = 20$$
$$x = 100 - 20=80$$
$$\dfrac x { ( y-x)} = \dfrac{80}{(100-80)}$$
So we get $$= \dfrac{80}{20}$$ ( Dividing by 20)
$$ =\dfrac 41 = 4$$

If x is 20% less than y , find: $$\dfrac x{y - x}$$

Consider $$y = 100 $$Reduction $$= 20\% = 20$$ $$x = 100 - 20=80$$$$\dfrac x { ( y-x)} = \dfrac{80}{(100-80)}$$So we get $$= \dfrac{80}{20}$$ ( Dividing by 20) $$ =\dfrac 41 = 4$$

Consider $$y = 100 $$
Reduction $$= 20\% = 20$$
$$x = 100 - 20=80$$
$$\dfrac x { ( y-x)} = \dfrac{80}{(100-80)}$$
So we get $$= \dfrac{80}{20}$$ ( Dividing by 20)
$$ =\dfrac 41 = 4$$