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Question

If x+iy=(a+ib)/(c+id), then (x2+y2)2=(a2+b2)/(c2+d2). If this is true enter 1, else enter 0.

Solution
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x+iy=(a+ib)/(c+id)
by taking modulus
|x+iy|=a+ibc+id
x2+y2= a2+b2c2+d2
x2+y2=a2+b2c2+d2
(x2+y2)2=a2+b2c2+d2
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