If x, v and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period T, then, which of the following does not change with time?
a2T2+4π2v2
aTx
aT+2πv
aTv
A
aTx
B
a2T2+4π2v2
C
aT+2πv
D
aTv
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Solution
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aTx=ω2xTx=4π2T2T=4π2T=constant
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