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Question

If x+1<0 then |x| is
  1. 0
  2. x+1
  3. x
  4. x1
  5. x

A
0
B
x1
C
x
D
x
E
x+1
Solution
Verified by Toppr

x+1<0, which gives x<1, therefore x<0
Since x is negative, we get |x|=x>0.

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