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Question

If $x \neq y$ and $x, y$ are real numbers; and $A = x^{2} + y^{2} - x y - x - y + 1$ , then
$A > 0$
$A = 0$
$A < 0$
$0 < A < 1$

A

A = 0

B

A > 0

C

0 < A < 1

D

A < 0

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Solution

Verified by Toppr

$A = \frac{1}{2} (2 x^{2} + 2 y^{2} - 2 x y - 2 x - 2 y + 2)$

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