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Question

If $x = p - 2$ and $\frac{x}{p} - \frac{x + 1}{p} = 1$ , find $p$ .

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Solution

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$\frac{x -}{p}$ $\frac{x + 1}{p} = 1$
$\Rightarrow \frac{x - x - 1}{p} = 1$
$\Rightarrow \frac{- 1}{p} = 1$
$\Rightarrow p = - 1$

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