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Question

If (x+y):(y+z):(z+x)::5:11:12, then xy=
  1. 23
  2. 32
  3. 0
  4. 1

A
23
B
1
C
0
D
32
Solution
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Solution - Given that (x+y):(y+2):(z+x)5:11:12
This can be written as

x+y=5k(1)y+z=11k or z=11ky and z+x=12k11ky+x=12kxy=k(2)



on solving (1) and (2) we get x=3k ; y=2kxy=3k2k=32 Hence, (A) is the correct option.

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