Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

If $x^{y} + y^{x} = a^{b}$ , then show that $\frac{d y}{d x} = - (\frac{y x^{y - 1} + y^{x} log y}{x^{y} log x + x y^{x - 1}})$

Open in App

Solution

Verified by Toppr

Was this answer helpful?

38

Similar Questions

Q1

If

x^{y} + y^{x} = a^{b}

then show that

\frac{d y}{d x} = - [\frac{y x^{y - 1} + y^{x} log y}{x^{y} log x + x y^{x - 1}}]

View Solution

Q2

If

x^{y} = y^{x}

then show that

\frac{d y}{d x} = \frac{y (x log y - y)}{x (y log x - x)}

View Solution

Q3

If $x^{y} + y^{x} = a^{b}$ the find $\frac{d y}{d x}$ . OR
If $e^{y} (x + 1) = 1,$ then show that $\frac{d^{2} y}{d x^{2}} = {(\frac{d y}{d x})}^{2}$ .

View Solution

Q4

Solution of

\frac{d y}{d x} = \frac{y (x log y - y)}{x (y log x - x)}

is:

View Solution

Q5

If

x^{y} + y^{x} = a^{b}

, then find

\frac{d y}{d x}

.

View Solution