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Question

If $y = 2 sin x - 3 x^{4} + 8$ , then $\frac{d y}{d x}$ is
$2 sin x - 12 x^{3}$
$2 cos x - 12 x^{3}$
$2 cos x + 12 x^{3}$
$2 sin x + 12 x^{3}$

A

2 sin x - 12 x^{3}

B

2 cos x + 12 x^{3}

C

2 cos x - 12 x^{3}

D

2 sin x + 12 x^{3}

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Solution

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If $y = 2 sin x - 3 x^{4} + 8$
$\Rightarrow \frac{d y}{d x} = 2 cos x - 3 (4 x^{(4 - 1)}) + 0$
$\Rightarrow \frac{d y}{d x} = 2 cos x - 12 x^{3}$
Therefore, the correct answer is $B$ .

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