If you subtract dfrac-1-2- from a number and the obtained number is multiplied by the by dfrac-1-2- you get dfrac-1-8- What is the number- -

Question

Toppr Admin · Accepted Answer

Let be original number be -x-According to the given condition-x-dfrac-1-2-dfrac-1-2-dfrac-1-8-x-dfrac-1-2-dfrac-1-4-x-dfrac-1-2-dfrac-1-4-160- -160-dfrac-2-4-8-160- -160-dfrac-3-4-

If you subtract $$\dfrac{1}{2}$$ from a number and if the obtained number is multiplied by the by $$\dfrac{1}{2}$$, you get $$\dfrac{1}{8}$$ What is the number. ?

Let be original number be $$x$$

According to the given condition

$$(x-\dfrac{1}{2})(\dfrac{1}{2})=\dfrac{1}{8}$$

$$(x-\dfrac{1}{2})=\dfrac{1}{4}$$

$$x=\dfrac{1}{2}+\dfrac{1}{4}$$

$$=\dfrac{2+4}{8}$$

$$=\dfrac{3}{4}$$

If you subtract $$\dfrac{1}{2}$$ from a number and if the obtained number is multiplied by the by $$\dfrac{1}{2}$$, you get $$\dfrac{1}{8}$$ What is the number. ?

Let be original number be $$x$$According to the given condition$$(x-\dfrac{1}{2})(\dfrac{1}{2})=\dfrac{1}{8}$$$$(x-\dfrac{1}{2})=\dfrac{1}{4}$$$$x=\dfrac{1}{2}+\dfrac{1}{4}$$ $$=\dfrac{2+4}{8}$$ $$=\dfrac{3}{4}$$

Let be original number be $$x$$

According to the given condition

$$(x-\dfrac{1}{2})(\dfrac{1}{2})=\dfrac{1}{8}$$

$$(x-\dfrac{1}{2})=\dfrac{1}{4}$$

$$x=\dfrac{1}{2}+\dfrac{1}{4}$$

$$=\dfrac{2+4}{8}$$

$$=\dfrac{3}{4}$$