If 1 stands true and 0 stands false- then choose the correct code the following statement- H-2SO-4 is a weaker acid than HCl- yet HCl is evolved when conc- H-2SO-4 is added to NaCl-

Question

If 1 stands true and 0 stands false- then choose the correct code the following statement- H-2SO-4  is a weaker acid than HCl- yet HCl is evolved when conc- H-2SO-4  is added to NaCl-

Toppr Admin · Accepted Answer

H2SO4 exists in liquid formed but HCl forms in reaction is gaseous- so it escapes and shifts the equilibrium towards right-NaCl-H2SO4-x2192-NaHSO4-HCl

If 1 stands for true and 0 stands for false, then choose the correct code for the following statement:
$H_{2} S O_{4}$ is a weaker acid than $H C l$ , yet $H C l$ is evolved when conc. $H_{2} S O_{4}$ is added to $N a C l$ .

$H_{2} S O_{4}$ exists in liquid formed but HCl forms in reaction is gaseous, so it escapes and shifts the equilibrium towards right.
$N a C l + H_{2} S O_{4} \to N a H S O_{4} + H C l$

If 1 stands for true and 0 stands for false, then choose the correct code for the following statement:H2SO4 is a weaker acid than HCl, yet HCl is evolved when conc. H2SO4 is added to NaCl.

H2SO4 exists in liquid formed but HCl forms in reaction is gaseous, so it escapes and shifts the equilibrium towards right.NaCl+H2SO4→NaHSO4+HCl

If 1 stands for true and 0 stands for false, then choose the correct code for the following statement:
$H_{2} S O_{4}$ is a weaker acid than $H C l$ , yet $H C l$ is evolved when conc. $H_{2} S O_{4}$ is added to $N a C l$ .

$H_{2} S O_{4}$ exists in liquid formed but HCl forms in reaction is gaseous, so it escapes and shifts the equilibrium towards right.
$N a C l + H_{2} S O_{4} \to N a H S O_{4} + H C l$