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Question

If 250 mL of a solution contains 24.5 g $H_{2} S O_{4}$ the molarity and normality respectively are:
$1 M, 2 N$
$1 M, 0.5 M$
$0.5 M, 1 N$
$2 M, 1 N$

A

1 M, 2 N

B

2 M, 1 N

C

1 M, 0.5 M

D

0.5 M, 1 N

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Solution

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$250 m l \to 24.5$

$∴ 1 l \to 24.5 \times 4$

$= 98 g = 1 M$

$N o r m a l i t y = m o l a r i t y \times n f a c t o r$

$= 1 \times 2 = 2 N$

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